2x^2-248x-11520=0

Solution for 2x^2-248x-11520=0 equation:

2x^2-248x-11520=0

a = 2; b = -248; c = -11520;
Δ = b2-4ac
Δ = -2482-4·2·(-11520)
Δ = 153664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{153664}=392$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-248)-392}{2*2}=\frac{-144}{4}
=-36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-248)+392}{2*2}=\frac{640}{4}
=160
$